This page provides information about powering LEDs. This pertains to ordinary LEDs, not LASER LEDs
A given LED will operate with a characteristic "forward voltage" drop. There is also a continuous operation "current" limit. These parameters should be available from wherever you get the LED. In the case of Radio Shack parts, this information should be printed on the back of the package.
If you have no idea what the voltage drop is across your LED, consider the following rule of thumb:
| LED color | voltage |
|---|---|
| ordinary red | 1.7 Volts |
| special red: high-brightness, high-efficiency, or low-current | 1.9 Volts |
| orange or yellow | 2 Volts |
| green | 2.1 Volts |
| bright white, emerald green, and most blue-derived (phosphor) | 3.4 Volts |
| 430 nM bright blue | 3.5-3.8 Volts |
| U.V. | 4.6 Volts |
If you have no idea what to use for the current:
The LED will be connected in series with the battery and resistor.
This is a schematic diagram of a single LED hookup.
This is a pictorial diagram of a single LED hookup.
The resistor must handle whatever voltage from the battery that is not consumed by the LED. If we have a 9 Volt battery and a 1.7 Volt diode.
9 Volt battery - 1.7 Volt LED = 7.3 Volts in the resistorSo the resistor must take up the slack of 7.3 Volts. If we want 20 mA (.020 Amps) to flow through this circuit,
Resistance = Voltage / CurrentResistors come in certain standard resistance values. The next higher standard value resistor is 390 Ohms.365 Ohms = 7.3 Volts / .020 Amps
The voltage consumed by the resistor has to go somewhere. It is radiated as heat, and you must select a resistor wattage that can handle that power level.
Power = Current x VoltageResistors come in certain standard wattage values. A 1/4 Watt resistor should do it.0.146 Watts = .020 Amps x 7.3 Volts
Please note that the published current rating for a LED is a maximum value. It is perfectly safe to use less current (a larger resistor value); the LED will simply be less bright.
For the lazy, we offer a LED-resistor calculator.
This is a series wiring arrangement.
Note that the LEDs form a chain, cathode (short wire) to anode (long wire), cathode to anode.
It's OK if the LEDs are different sizes, colors, and/or brightness.
This works fine, as long as:
The math is still pretty simple. Let's take the example of 2 red (1.7V) and one green (2.1V) LED, with a 9V battery.
The resistor must handle whatever voltage from the battery that is not consumed by the LED. If we have a 9 Volt battery:
9 Volt battery - 1.7Voltled1 - 1.7Voltled2 - 2.1Voltled3 = 3.5 Volts in the resistorSo the resistor must take up the slack of 3.5 Volts. If we want 20 mA (.020 Amps) to flow through this circuit,
Resistance = Voltage / CurrentResistors come in certain standard resistance values. The next higher standard value resistor is 180 Ohms.175 Ohms = 3.5 Volts / .020 Amps
The voltage consumed by the resistor has to go somewhere. It is radiated as heat, and you must select a resistor wattage that can handle that power level.
Power = Current x VoltageResistors come in certain standard wattage values. A 1/8 Watt resistor should do it.0.07 Watts = .020 Amps x 3.5 Volts
Please note that the published current rating for a LED is a maximum value. It is perfectly safe to use less current (a larger resistor value); the LED will simply be less bright.
For the lazy, we offer a LED-resistor calculator for use with identical LEDs in series.
This is a parallel wiring arrangement.
Note that all of the LED cathodes (short wire) are hooked together,
and all of the anodes (long wire) are hooked together.
To make this parallel wiring scheme work, you calculate the resistor so that you get three times as much current running through the circuit. Then, each of the three LEDs consumes one third of the (triple) current, which is exactly what it needs. Neat. Simple. Wrong.
This scheme is predicated on the assumption that all of the LEDs need exactly the same amount of power. If this assumption is met, or fairly close to being met, this circuit will work.
If one of the three LEDs needs less power, the electricity will take the path of least resistance. That one "easy" LED will light brighter, and the other LEDs won't get enough power, and will be dim. Remember that you calculated the resistor for three times the current of a single LED. If the other LEDs don't take their fair share, the easy LED will get more power than it should.
But why might one LED need less power than the others?
So, your best chance of making LEDs operate in parallel is to do it with few LEDs, all of which are exactly the same model number, from the same batch. Even then, the system may collapse, as the components degrade at different rates over time.
Of course, this kind of thing works often enough that you can often get away with it. But why not buy a couple more resistors and do it the right way?
Don't believe me? Here are some references:
Note that the LEDs are connected in
series
to form a chain, cathode (short wire) to anode (long wire), cathode to anode.
The chains are wired in
parallel.
With different color LEDs, you will have to calculate different resistor and power supply values. If the power supply winds up too high with the number of LEDs that the board supports, you can choose either to jumper over some of the LED positions or cut the PC traces in the middle and jumper them around to make more strings.
This board carries 36 LEDs.
They are connected as 4 strings in parallel.
Each string consists of 9 LEDs and one resistor in series.
This board carries 72 LEDs, connected as 12 strings in parallel.
Each string consists of 6 LEDs and one resistor in series.
For the latest products and prices,
go to B. G. Micro
and search for "Illuminator".
Here's what they offered, as of October 1 2004.
| catalog# | Description | Price |
|---|---|---|
| LED1058 | IR Illuminator, PC Board Only | $7.50 |
| LED1071 | IR Illuminator, PC Board Only | $9.95 |
| LED1007 | IR Illuminator, small, kit | $12.95 |
| LED1072 | IR Illuminator, small, assembled | $19.95 |
| LED1069 | IR Illuminator, big, kit | $25.95 |
| LED1070 | IR Illuminator, big, assembled | $34.95 |
| LED1092 | IR Illuminator, 850nm IR 20 Degree, small, kit | $24.95 |
| LED1093 | IR Illuminator, 850nm IR 20 Degree, small, assembled | $34.95 |
| LED1094 | IR Illuminator, 850nm IR 20 Degree, big, kit | $46.50 |
| LED1095 | IR Illuminator, 850nm IR 20 Degree, big, assembled | $66.50 |
| LED1096 | IR Illuminator, 850nm IR 50 Degree, small, kit | $24.95 |
| LED1097 | IR Illuminator, 850nm IR 50 Degree, small, assembled | $34.95 |
| LED1098 | IR Illuminator, 850nm IR 50 Degree, big, kit | $46.50 |
| LED1099 | IR Illuminator, 850nm IR 50 Degree, big, assembled | $66.50 |
B. G. Micro also sells power supplies for these boards, but the power supplies are intended for I.R. LEDs. If you populate the boards with LEDs having different electrical characteristics, you will need a different power supply.
It is also possible to build a constant current source that will give the LED exactly the current that it needs. Since there is no excess to be burned up as heat, this type of power system is more efficient.
Note that a constant current source (current regulator) is different from a voltage regulator.
We hope to add more in this section soon, but in the meantime, we have a simple constant-current source used for a LED tester
This sometimes works.
If you are tempted to do this, I suggest that you carefully read the technical specifications for your LEDs and make sure that you won't be exceeding the peak reverse voltage.
In general, I try to avoid this kind of thing.
There are several ways to do it.
Use the LED-resistor calculator
to determine what resistor to use.
Good things about this approach:
What you need:
Make sure that the rectifier diode is rated for forward current of at least as much as the forward current of your
LEDs.
Make sure that the peak inverse voltage is at least as high as the line voltage in you area.
Use the LED-resistor calculator
to determine what resistor to use.
When the calculation requires voltage, use the peak voltage in your area:
Regulated DC Wall Wart
What you need:
pictorial diagram of hookup
Bad things about this approach:
Half-Wave Rectified Line Current
Warning: This is a "hot-chasis" circuit that could expose users to line current.
Do not try this unless you are familiar with the necessary safety precautions!
| location | nominal RMS voltage | peak voltage | peak-to-peak voltage |
|---|---|---|---|
| United States | 120 V | 170 V | 340 V |
| European Union | 230 V | 325 V | 650 V |
pictorial diagram of hookup
Example:
Good things about this approach:
What you need:
Make sure that the bridge rectifier is rated for forward current of at least as much as the forward current of your
LEDs.
Make sure that the peak inverse voltage is at least as high as the line voltage in you area.
Use the LED-resistor calculator
to determine what resistor to use.
When the calculation requires voltage, use the peak voltage in your area:
Full-Wave Rectified Line Current
Warning: This is a "hot-chasis" circuit that could expose users to line current.
Do not try this unless you are familiar with the necessary safety precautions!
| location | nominal RMS voltage | peak voltage | peak-to-peak voltage |
|---|---|---|---|
| United States | 120 V | 170 V | 340 V |
| European Union | 230 V | 325 V | 650 V |
pictorial diagram of hookup
Example:
Good things about this approach:
Let's say that the LED is rated for 20 mA, maximum continuous current.
You can run it all day long at 20 mA.
You can raise the current beyond the maximum continuous current
if the LED is only operated in pulses.
Here we show the same LED operated at twice the maximum continuous current,
but we are only running the LED half the time.
Now we're running the LED at four times the maximum continuous current,
but are only running the LED one quarter of the time.
You can keep increasing the current while reducing the duty cycle, up until you reach the absolute maximum pulse current, which should be documented someplace.
Please note that our manipulations increase the peak current, but since the time during which that current is applied reduces, overall the average current over time is the same.
The maximum continuous current derives from the efficiency of the LED and its ability to shed heat. Because no LED is 100% efficient at turning electricity into light, the wasted electrical energy turns into heat within the LED. If the heat builds up too high, the LED chip will melt. But excess heat can be conducted out of the LED package through the "lead frame" and metal lead wires. The maximum continuous current is the maximum current that you can feed through the LED that it is able to dissipate without heating up to damaging temperatures.
If the LED is not run continuously, it has time to shed some of the heat, and can be run at higher current levels.
So why did I say that pulsing LEDs for higher lower is an urban legend? Clearly you can pulse them and get higher power levels.
The average user of LEDs cares only about how bright the light is. The eye is slow to react, and registers the average brightness of the light. Although it is true that we have increased the instantaneous brightness of the light, average brightness (that the eye sees) is the same.
The only time that you get something by pulsing is when you were going to pulse the LED anyway, perhaps as a carrier signal. If you know the duty cycle of the pulse, you can increase the drive current beyond the specified maximum continuous current.
To figure out the real limits, you have to read the data sheets.
But if you want maximum performance, or intend to push any of the operating parameters, you need detailed data sheets. This is because many of the figures quoted in short data sheets is an average, and the real values vary significantly depending on other conditions.
Note: Getting this information is sometimes difficult. LEDs from many of the hobby vendors come with little or no information. You're lucky to find a couple of lines on the back of a blister pack from Radio Shack.
Most of the following graphs were taken from the data sheet for the Optosource 110147 series, kindly provided by Wolfstone reader Ronald Jansen. These graphs are used only for illustrative purposes, and are unlikely to match your LEDs, unless you happen to use the Optosource 110147 series.
This graph shows Ambient Temperature vs. Allowable Forward Current.
Heat kills LEDs, and the heat can come from outside the LED or inside. The amount of heat generated within the LED depends on the current, so the hotter it is outside, the less current you can use before the total heat cooks the part.
At 80°C, the LED is already so hot that you can't run it at all.
[Optosource, a division of Marl International Limited, www.optosource.com]
This graph shows Ambient Temperature vs. Forward Voltage for three different current levels.
The temperature of the LED chip affects its electrical characteristics.
As the LED gets hotter, the forward voltage decreases. This effect is more pronounced at higher current levels.
[Optosource, a division of Marl International Limited, www.optosource.com]
This graph shows Ambient Temperature vs. Luminosity on a semi-log scale.
This LED puts out less light as it gets hotter.
[Optosource, a division of Marl International Limited, www.optosource.com]
This graph shows Forward Voltage vs Forward Current on a semi-log scale.
The more current that you shove through, the higher the forward voltage. This complicates pulse driving LEDs.
[Optosource, a division of Marl International Limited, www.optosource.com]
This graph shows Forward Current vs Luminosity.
The more current, the brighter the LED, and it's fairly linear.
[Optosource, a division of Marl International Limited, www.optosource.com]
This graph shows Duty Cycle vs Allowable Forward Current
using a log-log scale.
If your LED data sheet contains a graph like this, you can easily determine the limits for pulse driving LEDs.
[Optosource, a division of Marl International Limited, www.optosource.com]
This graph shows the spectrum of light output for a white LED.
Please note the current and temperature notations in the upper right.
[Optosource, a division of Marl International Limited, www.optosource.com]
White LEDs are made by painting the chip of a blue LED with fluorescent phosphors to change the spectrum of emitted light.
This graph shows the
CIE chromaticity coordinates
for the color of light output by a white LED
operated at four different current levels.
Increasing current will raise internal temperature, which has an effect on the phosphors. It also increases the primary emitter output, and the various phosphors in the mix may not react uniformly to increased optical input.
[Nichia model NEPW500 white LED]
This graph shows the
CIE chromaticity coordinates
for the color of light output by a white LED
operated at five different temperatures.
The ambient temperature certainly has an effect on the LED's primary emitter, but probably has a greater effect on the phosphors.
[Nichia model NEPW500 white LED]
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